Answer:
= - √3/3
Explanation:
Tan ( 11π/6)
= Tan ( (12π - 11π)/6)
= Tan ( 2π - π/6)
using Tan ( A - B) = (Tan A - TanB)/(1 + TanATanB)
A = 2π B = π/6
= (Tan 2π - Tan π/6)/( 1 + Tan2π * Tan(π/6)
Tan 2π = 0
=> ( 0 - Tan π/6)/(1 + 0)
= - Tan π/6
Tan π/6 = √3/3
= - √3/3