Answer:
13, 15, 17
Explanation:
Each digit must be odd, and to get consecutive odd integers, you must add using the multiple of 2:
Let the least number be "x". Set the equation:
(x) + (x + 2) + (x + 4) = 45
Isolate the variable, x. First, combine like terms:
(x + x + x) + (2 + 4) = 45
(3x) + 6 = 45
Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Subtract 6 from both sides:
3x + 6 (-6) = 45 (-6)
3x = 45 - 6
3x = 39
Divide 3 from both sides:
(3x)/3 = (39)/3
x = 39/3
x = 13
Your first number (x) is 13. Solve for the other 2 numbers:
(x) = 13
(x + 2) = 13 + 2 = 15
(x + 4) = 13 + 4 = 17
13, 15, 17 are your numbers:
Check:
13 + 15 + 17 = (13 + 15) + 17 = 28 + 17 = 45
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