Answer:
1a. 0.89 gcm¯³
1b. Yes.
1c. Tetrahydrofuran.
2. 0.54 g/mL
Step-by-step explanation:
1. Data obtained from the question include:
Volume = 0.988 L = 988 cm³
Mass = 879 g
1a. Determination of the density
Density = mass /volume
Density = 879/ 988
Density = 0.89 gcm¯³
Therefore, the density of the liquid is 0.89 gcm¯³
1b. From the given data, it is possible to determine the identity of the liquid.
1c. The density of the liquid is 0.89 gcm¯³. Comparing the density of the liquid obtained with those given in the table, the liquid is tetrahydrofuran
2. Data obtained from the question include:
Mass of empty cylinder = 5.25 g
Mass of cylinder and sodium thiosulfate = 75.82 g
Volume = 130.63 mL
Next, we shall determine the mass of sodium thiosulfate. This can be obtain as follow:
Mass of empty cylinder = 5.25 g
Mass of cylinder and sodium thiosulfate = 75.82 g
Mass of sodium thiosulfate =.?
Mass of sodium thiosulfate = Mass of cylinder and sodium thiosulfate – Mass of empty cylinder
Mass of sodium thiosulfate = 75.82 – 5.25
Mass of sodium thiosulfate = 70.57 g
Finally, we shall determine the concentration of the sodium thiosulfate as follow:
Mass = 70.57 g
Volume = 130.63 mL
Concentration =?
Concentration = mass /volume
Concentration = 70.57/130.63
Concentration = 0.54 g/mL
The concentration of the solution is 0.54 g/mL