Question

How many moles of 0.225 M CaOH2 are present in 0.350 L of solution?

Calculate the number of moles of solute (CaOH2)

( M CaOH2)
(0.350 L
) = mol CaOH2

Answer 1

(0.225 M CaOH2) x (0.350 L) = 0.0788 mol CaOH2

Step-by-step explanation:

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For the second question: How many grams of CaOH2 are in this solution?

The molar mass of CaOH2 is 58.093 g/mol.

Answer:

(0.0787 mol CaOH2) x (58.093 g/mol) = 4.57g CaOH2

Step-by-step explanation:

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Answer 2

Answer : The number of moles of solute
`Ca(OH)_2` is, 0.0788 moles.

Explanation : Given,

Molarity = 0.225 M

Volume of solution = 0.350 L

Formula used:

`\text{Molarity}=\frac{\text{Moles of }Ca(OH)_2}{\text{Volume of solution (in L)}}`

Now put all the given values in this formula, we get:

`0.225M=\frac{\text{Moles of }Ca(OH)_2}{0.350L}`

`\text{Moles of }Ca(OH)_2=0.0788mol`

Therefore, the number of moles of solute
`Ca(OH)_2` is, 0.0788 moles.