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Let the test statistic T have a t distribution when H0 is true. Give the significance level for each of the following situation.

A. Ha: mu > m0, df = 15, rejection region t > 3.733
B. Ha : mu < mu 0, n = 24, rejection region t < - 2.500
C. Ha: mu not = mu 0, n = 31, rejection region t >1.697 or t < - 1.697

User Ceekay
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1 Answer

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Answer:

a) The degrees of freedom are given by:


df = 15

And the rejection region is
t_(\alpha)<3.733

And the significance level would be:


P(t_(15) >3.733) =0.001

b) The degrees of freedom are given by:


df = 24-1=23

And the rejection region is
t_(\alpha) <-2.5

And the significance level would be:


P(t_(23) <-2.5) =0.0099 \approx 0.01

c) The degrees of freedom are given by:


df = 31-1=30

And the rejection region is
t_(\alpha) <-1.697 or
t_(\alpha) >1.697

And the significance level would be:


2*P(t_(30) <-1.697) =0.10

Explanation:

Part a

We have the following system of hypothesis:

Null hypothesis:
\mu \leq \mu_0

Alternative hypothesis:
\mu > \mu_0

The degrees of freedom are given by:


df = 15

And the rejection region is
t_(\alpha)<3.733

And the significance level would be:


P(t_(15) >3.733) =0.001

Part b

We have the following system of hypothesis:

Null hypothesis:
\mu \geq \mu_0

Alternative hypothesis:
\mu < \mu_0

The degrees of freedom are given by:


df = 24-1=23

And the rejection region is
t_(\alpha) <-2.5

And the significance level would be:


P(t_(23) <-2.5) =0.0099 \approx 0.01

Part c

We have the following system of hypothesis:

Null hypothesis:
\mu = \mu_0

Alternative hypothesis:
\mu \\eq \mu_o

The degrees of freedom are given by:


df = 31-1=30

And the rejection region is
t_(\alpha) <-1.697 or
t_(\alpha) >1.697

And the significance level would be:


2*P(t_(30) <-1.697) =0.10

User Umlum
by
4.6k points
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