Question

Solve the system of equations.

Answer 1

C. (-4, 11) and (2, -1)

Explanation:

`x^2-5=-2x+3\\\\x^2+2x-8=0\\\\a=1\,,\ b=2\,,\ c=-8\\\\x=(-b\pm√(b^2-4ac))/(2a)\\\\x=(-2\pm√(2^2-4\cdot1\cdot(-8)))/(2\cdot1)=(-2\pm√(4+32))/(2)=(-2\pm√(36))/(2)=(-2\pm6)/(2)\\\\x_1=\frac{-2-6}2=\frac{-8}2=-4\\\\y_1=-2x_1+3=-2(-4)+3=8+3=11\\\\(-4\,,\ 11)\\\\x_2=(-2+6)/(2)=\frac{4}2=2\\\\y_2=-2x_2+3=-2\cdot2+3=-4+3=-1\\\\(2\,,\ -1)`