Question

(HELP ASAP!)

Write and solve an equation using the descriptions below.

Ten less than the quotient of a number and 3 is 6.

Seven plus the quotient of a number and 5 is -12.

Eight times the difference of a number and 3 is 40.

The difference of twice a number and 7 is 9.

Answer 1

3 divided by n -10= 6

Answer 2

Explanation:

1) Let the number be x

Quotient of a number & 3 : x/3

Ten less than the quotient of a number : (x/3) -10

`(x)/(3)-10=6`

Add 10 to both sides

`(x)/(3)-10+10=6+10\\\\(x)/(3)=16`

Multiply both sides by 3

`(x)/(3)*3=16*3\\\\x=48`

2) Let the number be x

Quotient of a number & 5 : x/5

Seven plus the quotient of a number : (x/5)+7

`(x)/(5)+7=-12\\`

Subtract 7 form both sides

`(x)/(5)+7-7=-12-7\\\\ (x)/(5)=-19\\`

Multiply both sides by 5

x = -19*5

x = -95

3) Let the number be x

Difference of a number and 3 : x - 3

Eight time the difference of a number & 3: 8*(x-3)

8*(x - 3 ) = 40

Divide both sides by 8

`(8*(x-3))/(8)=(40)/(8)`

x - 3 = 5

Add 3 to both sides

x - 3 +3 = 5 +3

x = 8

4) Let x be the number

Twice a number : 2x

The difference of twice a number and 7: 2x - 7

2x - 7 = 9

Add 7 to both sides

2x - 7 + 7 = 9 + 7

2x = 16

Divide both sides by 2

2x/2 = 16/2

x = 8