Question

Determine whether each function is even, odd, or neither.g(x) = |x-3| g(x) = x + x

Answer 1

Explanation:

g(x) = |x-3| is neither even nor odd; the graph is not symmetric about the y-axis (as characterizes even functions), and is not symmetric about the origin either.

g(x) = x + x is actually g(x) = 2x, which is an odd function. The graph is symmetric about the origin.