137k views
2 votes
80 POINTS!!!!!!!!!!! What is the y-intercept of the line perpendicular to the line y = x + 1 that includes the point (4, 1)? 2 4

User Jheriko
by
8.3k points

2 Answers

7 votes

Answer:

y=5

Explanation:

Recall that for a linear equation y = mx + b,

the gradient of the line is m and the gradient of a line perpendicular to this line is the negative reciprocal of m,

i.e:

gradient of line perpendicular to gradient m = -1/m

In our case, we are given y = x+1.

Compared to the general equation above, gradient m = 1

hence the gradient of a perpendicular line = -1/m = -1/1 = -1

therefore the perpendicular line will take the form:

y = (-1) x + b

y = -x + b, where b is the y-intercept.

We are also given that the perpendicular line passes through (4,1), we simply substitute x = 4, y = 1 into the equation

y = -x + b

1 = -4 + b (add 4 to both sides)

1 + 4 = b

b = 5

Hence the y-intercept is y=5

User Jim Ratliff
by
9.0k points
2 votes

Answer:

y-intercept = 1

Explanation:


y = x + 1\\Let ; x =0\\y = 0+1\\y = 1

User Jorge Alvarado
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories