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80 POINTS!!!!!!!!!!! What is the y-intercept of the line perpendicular to the line y = x + 1 that includes the point (4, 1)? 2 4

User Jheriko
by
6.8k points

2 Answers

7 votes

Answer:

y=5

Explanation:

Recall that for a linear equation y = mx + b,

the gradient of the line is m and the gradient of a line perpendicular to this line is the negative reciprocal of m,

i.e:

gradient of line perpendicular to gradient m = -1/m

In our case, we are given y = x+1.

Compared to the general equation above, gradient m = 1

hence the gradient of a perpendicular line = -1/m = -1/1 = -1

therefore the perpendicular line will take the form:

y = (-1) x + b

y = -x + b, where b is the y-intercept.

We are also given that the perpendicular line passes through (4,1), we simply substitute x = 4, y = 1 into the equation

y = -x + b

1 = -4 + b (add 4 to both sides)

1 + 4 = b

b = 5

Hence the y-intercept is y=5

User Jim Ratliff
by
7.3k points
2 votes

Answer:

y-intercept = 1

Explanation:


y = x + 1\\Let ; x =0\\y = 0+1\\y = 1

User Jorge Alvarado
by
6.5k points
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