Question

Two particles with positive charges q1 = 0.480nC and q2 = 7.60nC are separated by a distance of 1.16m. At what point along the line connecting the two charges is the total electric field due to the two charges equal to zero?

Answer 1

Step-by-step explanation:

Electric field E = k Q / R²

k = 9 x 10⁹ , Q is charge and R is distance of point from the charge where field is to be found .

Electric field due to q₁ at distance x where total field is zero

E₁ = k x .48 x 10⁻⁹ / x²

Electric field due to other charge at that point

E₂ = k x 7.6 x 10⁻⁹ /( 1.16-x )²

For net field to be zero , E₁ and E₂ should be equal and opposite

k x .48 x 10⁻⁹ / x² = k x 7.6 x 10⁻⁹ /( 1.16-x )²

(1.16 - x )² / x² = 7.6 / .48 = 15.8333

1.16 - x / x = ±3.979

1.16 - x = 3.979 x

1.16 = 4.979 x

x = .233 m

distance from other charge

= 1.16 - .233

= .927 m .