- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -
![\blue{\textsf{\textbf{\underline{\underline{Question:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/71x195i00boerc1lgwqqaativxg02xh0cv.png)
Solve x²-5x+6
![\blue{\textsf{\textbf{\underline{\underline{Answer:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/3plsxq5h9x1ejyvsn8i00cr2kvbe8hatwk.png)
(x-2)(x-3)
![\blue{\textsf{\textbf{\underline{\underline{How\:to\:Solve:-}}}}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ylkdu099supg06setxoxzbt0st3v5yd6vh.png)
First, we think of two numbers such that
If we multiply them, we'll get 6
If we add them, we'll get -5
These numbers are -2 and -3.
Write them here:
(x-2)(x-3)
Now, how do we get (x-2)(x-3) from x(x-2)-3(x-2)?
Notice that (x-2) is the common term, so we factor it out:
(x-2)
And now, we write the other two terms that are left in the parentheses:
(And the terms left are x and -3)
(x-2)(x-3)
Notice that we ended up with the same answer.
Good luck.
- - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - - -