36.6k views
5 votes
A 1.555 g sample of baking soda decomposes with heat to produce 0.991 g Na2CO3. What is the percent yield of sodium carbonate, Na2CO3?

User Blubberbo
by
5.5k points

1 Answer

4 votes

Answer:

Step-by-step explanation:

Baking soda decomposes to produce sodium carbonate .

2NaHCO₃ = Na₂CO₃ + CO₂ + H₂O.

2 x 84 g 106 + 10 x 18 g

Molecular mass of Na₂CO₃ .10H₂O = 286

168 g baking soda produces 286 g sodium carbonate

1.555g baking soda will produce 286 x 1.555 / 168

= 2.647 g

Percentage yield = actual yield / theoretical yield x 100

= ( .991 /2.647 ) x 100

= 37.43 %.

User Keithhackbarth
by
5.3k points