Explanation:
Correct option is A)
Let Q(h,k) be the image of P(3,3) w.r.t the line mirror x+y=0
a
h−p
=
b
k−q
=
a
2
+b
2
−2×(ap+bq+c)
1
h−3
=
1
k−3
=
2
−2(6)
⇒h−3=k−3=−6
⇒h=−3,k=−3
So, the image is Q(−3,−3).
In the second transformation, point Q is translated horizontally 3 units to the left and vertically 3 units up.
So, the coordinates of new image is (−3−3,−3+3) i.e. (−6,0)
In the third transformation, point (−6,0) is reflected w.r.t the line y=x
So, the final image is (0,−6).
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