Question

Triangle ABC is an isosceles triangle in which side AB = AC. What is the perimeter of triangle ABC? 5 + StartRoot 10 EndRoot units 10 + StartRoot 10 EndRoot units 10 StartRoot 10 EndRoot units 50 units

Answer 1

Option (2)

Explanation:

This question is incomplete; find the picture attached which makes this question complete.

Vertices of the given triangle are A(-2, -4), B(2, -1) and C(3, -4).

Length of AB =
`√((x_1-x_2)^2+(y_1-y_2)^2)`

AB =
`√((2+2)^2+(-1+4)^2)`

=
`√(16+9)`

= 5 units

Since AB = AC

AC = 5 units

Similarly, BC =
`√((3-2)^2+(-4+1)^2)`

BC =
`√(10)` units

Therefore, perimeter of the given triangle = AB + AC + BC

= 5 + 5 + √10

= (10 + √10) units

Option (2) will be the answer.