Answer:
Explanation:
take a right triangle ABC...
right angled at B...
let AB be the height of the water tank...=52feet
AC hypotanuse...
BC is the length of the shadow..=78feet
tan thete=Opp/adj=AB/BC=52/78------eq1
tan theta in both cases remain the same,
hence,
take a right triangle PQR...
right angled at Q...
let PQ be the height of the water tank...
PR hypotanuse...
QR is the length of the shadow...=6feet
tan theta=52/78 (from 1)
tan thete=Opp/adj=PQ/QR = PQ/6-----eq2
hence, from 1, 2
52/78=PQ/6....
52x 6/78=PQ
52/13=PQ
Hence,4m=PQ=height of the boy...
Thank you, Hope this helps you dear friend,,,,