Answer:
A. There is a focus at (0,−10).
Explanation:
Assume the hyperbola is like the one below.
The hyperbola is vertical and centred on the y-axis, so its general equation is
![(y^(2))/(a^(2)) - (x^(2))/(b^(2)) = 1](https://img.qammunity.org/2021/formulas/mathematics/high-school/rw0le75nmfg1tmfoqqvuwylfahn76hwwz5.png)
The vertices of your parabola are (0,±8) so a = 8.
The covertices are (±6,0), so b = 6.
Calculate c
![\begin{array}{rcl}a^(2) + b^(2) & = & c^(2)\\8^(2) + 6^(2) & = & c^(2)\\64 + 36 & = & c^(2)\\100 & = & c^(2)\\c & = & \mathbf{10}\\\end{array}](https://img.qammunity.org/2021/formulas/mathematics/high-school/o1wq4kqzbks2ax5b2snd2kdz8byjcdt22p.png)
A. Foci
The foci are at (0, ±c) = (0, ±10)
TRUE. There is a focus at (0,-10).
B. Foci
The foci are at (0,±10).
False. There is no focus at (0,12)
C. and D. Asymptotes
The equations for the asymptotes are
![y = \pm(a)/(b)x = \pm(8)/(6)x = \pm(4)/(3)x](https://img.qammunity.org/2021/formulas/mathematics/high-school/wkray3bv5mo58hjzkxgtyetljes3gk13t8.png)
So, y = ±x are not asymptotes.
False.
E. and F. Directrices
The equations of the directrices are
y = ±a²/c = ±64/10 = ±6.4
y = 6.4 is a directrix.
E is false. x = cannot be a directrix
F is uncertain. Your equation for the directrix is incomplete.