60.4k views
2 votes
For the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

4Al(s) + 302(g) —> 2Al2O3(s)
Express your answer as a chemical formula.

1 mol Al; 1 mol O2
4 mol Al; 2.5 mol O2
12 mol Al; 10 mol O2
15.4 mol Al; 10.7 mol O2

User Ajl
by
4.5k points

1 Answer

2 votes

Answer:

1 mol Al; 1 mol O2

Explanation:ol Al; 10 mol O2

15.4 mol Al; 10.7 mol O2

or the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

4Al(s) + 302(g) —> 2Al2O3(s)

Express your answer aor the reaction shown, find the limiting reactant for each of the initial quantities of reactants.

4Al(s) + 302(g) —> 2Al2O3(s)

Express your answer as a chemical formula.

1 mol Al; 1 mol O2

4 mol Al; 2.5 mol O2

12 mol Al; 10 mol O2

15.4 mol Al; 10.7 mol O2

Hold on, our servers are swamped. Wait for your answer to fully load.s a chemical formula.

User Chys
by
4.3k points