Answer:
0.0236 m per minute,
Explanation:
Volume of the cone V = 1/3 π r^2 h.
Diameter = 2r = 2h so r = h
and V = 1/3 π h^3
So the rate of change of volume with height =
dV / dh = π h^2.
We are given that dV/dt = 6.
So the rate of change of height: dh/dt = dV/dt * dh/dV
= 6 * 1/ π h^2
When h = 9
dh/dt = 6 / 81π m per minute
= 0.0236 m per minute,