Question

Identify an equation in point-form for the line perpendicular to y=-1/3x-6 that pass through -1,5

Answer 1

y - 5 = 3(x + 1).

Explanation:

y = -1/3x - 6

The slope of this line is -1/3 so the slope of the perpendicular line to it is -1/-1/3

= 3.

Using the point-slope form of a straight line:

y - y1 = m(x - x1) where m = the slope and (x1, y1) is a point on the line:

Here m = 3 and (x1, y1) is (-1, 5) so we have:

y - 5 = 3(x - (-1))

y - 5 = 3(x + 1).

Answer 2

y=3x+8

Explanation:

Perpendicular to -1/3, is 3.

y-5=3(x+1)

y-5=3x+3

y=3x+8