Question

2 Points

What is the vertex of the graph of this equation y=-4x2 - 16x - 12?
O A. (-2,-4)
O B. (2, 4)
O C. (2, -4)
D. (-2,4)


Help need this solved fast

Answer 1

D

Explanation:

Given a parabola in standard form, y = ax² + bx + c ( a ≠ 0 )

Then the x- coordinate of the vertex is

`x_(vertex)` = -
`(b)/(2a)`

y = - 4x² - 16x - 12 ← is in standard form

with a = - 4 and b = - 16 , thus

`x_(vertex)` = -
`(-16)/(-8)` = - 2

Substitute x = - 2 into y for corresponding y- coordinate

y = - 4(- 2)² - 16(- 2) - 12 = - 16 + 32 - 12 = 4

vertex = (- 2, 4 ) → D