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Factor by using the difference of two cubes
(2x)³- 8 ​

User Txxwq
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1 Answer

2 votes

Answer:


(2x + 2)( {4x}^(2) - 4x + 4)

Solution,


{(2x)}^(3) - 8 \\


( {2x)}^(3) - {(2)}^(3)

Use the formula:


{a}^(3) - {b}^(3) = (a + b)( {a}^(2) - ab + {b}^(2) )

now,


(2x + 2)( {(2x)}^(2) - 2x * 2 + {(2)}^(2) )


(2x + 2)( {4x}^(2) - 4x + 4)

Hope this helps...

Good luck on your assignment...

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