Answer: CB=2/3
Explanation:
The triangle's angles are 30-60-90 degrees. So This is right triangle.
Let the triangle is ABC. B is right angle=90 degr . A=30 degrees, C=60 degrees
The long side of right triangle is hypotenuse AC=4/3 units.
In right triangle with 30 degr the side CB that is opposite to acute angle 30 degrees is twice shorter than hypotenuse AC
So CB=4/3/2=2/3
Finally using Pithagor theorem we find AB= sqrt( AC^2-CB^2)=
=sqrt(16/9-4/9)=sqrt(12/9)= 2*sqrt(3)/3
2*sqrt(3)/3>2/3 so AB>CB
So the shortest leg of ABC is CB=2/3