Two charges of +2.6 μC and –5.4 μC experience an attractive force of 6.5 mN. What is the separation between the charges?

asked Sep 16, 2023 163k views

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Answer:

Step-by-step explanation:

$q_(1) =+2.6 X10^(_-6)C \\q_(2) =-5.4 X10^(_-6)C \\F=6.5mN\\F=(Kq_(1)q_(2) )/(d^(2) )$

Murat Tutumlu answered Sep 20, 2023

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