Question

How do I get the derivative of y=xtanx ?

Answer 1

`(dy)/(dx)\ = tanx + x *sec^(2)x`

Explanation:

`y=xtanx`

Differentiate with respect to x by using product rule .

`y=xtanx\\\\(dy)/(dx)\ = tanx * (dx)/(dx)\ + x * (d(tanx\ ))/(dx) \\As\ \ [(d(tanx))/(dx) =(1)/(sec^(2)x ) \ ]\ so\\\\\\\\\`

`(dy)/(dx)\ = tanx + x * (1)/(cos^(2)x \ ) \\(dy)/(dx)\ = tanx + x *sec^(2)x`