How do I get the derivative of y=xtanx ?

asked Feb 23, 2021 126k views

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5 votes

Answer:

$(dy)/(dx)\ = tanx + x *sec^(2)x$

Explanation:

y=xtanx

Differentiate with respect to x by using product rule .

$y=xtanx\\\\(dy)/(dx)\ = tanx * (dx)/(dx)\ + x * (d(tanx\ ))/(dx) \\As\ \ [(d(tanx))/(dx) =(1)/(sec^(2)x ) \ ]\ so\\\\\\\\\$

$(dy)/(dx)\ = tanx + x * (1)/(cos^(2)x \ ) \\(dy)/(dx)\ = tanx + x *sec^(2)x$

Coffee Maker answered Mar 1, 2021

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