Question

Suppose that a computer chip company has just shipped 10 comma 000 computer chips to a computer company.​ Unfortunately, 40 of the chips are defective. ​(a) Compute the probability that two randomly selected chips are defective using conditional probability. ​(b) The probability that the first randomly selected chip is defective is StartFraction 40 Over 10 comma 000 EndFraction equals 0.004 equals 0.4 % . Compute the probability that two randomly selected chips are defective under the assumption of independent events. ​(a) The probability is nothing.

Answer 1

approx 0,000016 or 0,0016%

Explanation:

The probability that first selected chip is defective is 40/10000=4/1000

So only 39 defective chps left amoung 9999 chips.

So the probability that second randomly selected chip is defective as well is

39/9999= 13/3333=approx 0.004

The probability that both chips are defective is

P(both=defective)=0.004*0.004= 0.000016 or 0.0016%