21.8k views
3 votes
Consider the following quadratic equation. -4x^2+bx-11=0 Determine a possible value of b so that the quadratic has two complex solutions.

2 Answers

1 vote

Answer:

Explanation:

hello,

for
ax^2+bx+c=0


\Delta = b^2-4ac

so here


\Delta = b^2-4*(-4)*(-11)=b^2-176

to have two complex solutions we need
\Delta < 0\\

so
b^2<176


<=> b < √(176)=13.266...

for instance we can take b = 0

hope this helps

User Marco Pantaleoni
by
9.3k points
3 votes

Answer:

The correct answer is 12.

Explanation:

i got it correct on my test, thanks to comment on the question above.

User Jithinpt
by
7.8k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories