Question

Consider the following quadratic equation. -4x^2+bx-11=0 Determine a possible value of b so that the quadratic has two complex solutions.

Answer 1

Explanation:

hello,

for
`ax^2+bx+c=0`

`\Delta = b^2-4ac`

so here

`\Delta = b^2-4*(-4)*(-11)=b^2-176`

to have two complex solutions we need
`\Delta < 0\\`

so
`b^2<176`

`<=> b < √(176)=13.266...`

for instance we can take b = 0

hope this helps

Answer 2

The correct answer is 12.

Explanation:

i got it correct on my test, thanks to comment on the question above.