Question

The manometer of a reactor indicates a pressure of 2637.5 mmHg. It is known that the atmospheric pressure at this location is 13.6 psi. In these conditions, what is the pressure observed in the reactor, in kPa.

Answer 1

445 kPa

Step-by-step explanation:

Use for conversion rates:

101.325 kPa = 760 mmHg = 14.7 psi

2637.5 mmHg × (101.325 kPa / 760 mmHg) = 351.6 kPa

13.6 psi × (101.325 kPa / 14.7 psi) = 93.7 kpa

The total pressure is:

351.6 kPa + 93.7 kPa = 445.3 kPa

Rounded to three significant figures, the pressure is 445 kPa.