Question

Determine the equation of the line through (1,-2) and (-5,6)

Answer 1

1. First, find the slope using rise over run (y2-y1/x2-x1). This will give us ((6-(-2))/(-5-1)) or -4/3.
2. Next, plug the slope into our point-slope formula using either point: y-y1=m(x-x1) where m=slope. So we'll get y+2=(-4/3)(x-1)
3. Now we simplify to get y by itself:

y+2=-4x/3+4/3, y=-4x/3-2/3

So our equation of our line is y=-4x/3-2/3!

Answer 2

Slope: (6 - (-2)) / (-5 - 1) = 8 / -6 = -4/3

Point slope form (i'm using the point (1, -2) but it doesn't matter which one you use): y - (-2) = -4/3(x - 1)

y + 2 = -4/3x + 4/3

y = -4/3x - 2/3