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what is the interquartile range range to 457, 548, 866, 952, 976, 1037, 1148, 1235, 1245, 1431, 1486, 1759, 1864 Please help fast

2 Answers

2 votes

Answer:

549.5

Explanation:

User Rajendran Nadar
by
4.6k points
5 votes

Answer:

The interquartile range is 549.5

Explanation:

This is probably too late, but whatever.

1. To find the IQR, put the numbers in order. (least to greatest)

(457, 548, 866, 952, 976, 1037, 1148, 1235, 1245, 1431, 1486, 1759, 1864)

2. Find the median.

(457, 548, 866, 952, 976, 1037, 1148, 1235, 1245, 1431, 1486, 1759, 1864)

The median is 1148.

3. Seperate the numbers above and below the median by using parentheses.

(457, 548, 866, 952, 976, 1037) 1148 (1235, 1245, 1431, 1486, 1759, 1864)

4. Find Q1 and Q3. These are the medians of the numbers above and below 1148, respectively.

Q1 is the median of (457, 548, 866, 952, 976, 1037) = 866+952/2 = 909

Q1 = 909

Q3 is the median of (1235, 1245, 1431, 1486, 1759, 1864)

1431+1486/2=1458.5

Q3 = 1458.5

Subtract Q1 from Q3 to find the interquartile range.

Q3- Q1

1458.5 - 909 = 549.5

The interquartile range is 549.5 .

User Tekumara
by
4.8k points