Question

Mr. Lee left his fortune to his 3 sons, 4 daughters and his wife. Each son received twice as much as each daughter and his wife received $6000, which was a quarter of the money. How much did each son receive?

Answer 1

He have 3 sons, 4 daughters and his wife.

His wife got $6000 from his fortune which is 1/4th of his fortune.

So.. 1/4x=$6000

Multiply both by 4, 1/4 multiply by 4 is 4/4=1,

So.. 1x=$24000

Now subtract the wife's share from the fortune

$24000-$6000=$18000

His have 3 sons and 4 daughters left, and his each son got twice more than each daughter

So... 18000=3(2x) +4(x)

18000 =6x +4x

18000=10x

x=18000÷10

=$1800 which is for each daughter

his each son got twice as much as each daughter

So.. 2 multiply by $1800

which is $3600.

so each son got $3600

If you are still not sure then add all the shares together

3(3600)+ 4(1800)+ 6000

=10800 +7200+ 6000

=$24000.

THERE YOU HAVE IT, THE ANSWER IS $3600

NGL even I didn't now but I got it from the answer above

So all the credit goes to the person who answered before me

Answer 2

Hey there! :)

Answer:

$3600.

Explanation:

If the wife received $6000 which is a quarter of the money, solve for the total amount of the fortune:

1/4x = 6000

Multiply both sides by 4:

x = $24000

We can begin by subtracting the wife's amount from the total:

24000 - 6000 = $18000

He has 3 sons and 4 daughters. Let 'x' represent the amount the daughters received, and '2x' the amount the sons received.

18000 = 3(2x) + 4(x)

Distribute and combine the terms:

18000 = 6x + 4x

18000 = 10x

Divide both sides by 10:

18000/10 = 10x/10

x = $1800. This is the amount that each daughter receives. Since the sons receive '2x':

2(1800) = $3600.