78.4k views
2 votes
Evaluate. Write your answer as a fraction or whole number without exponents. 7^–1 =

2 Answers

6 votes

Answer:

1/7 = 0.142857... repeating

Explanation:

7^(-1) = 1/(7^1) =1/7 = 0.142857... repeating

User Vladimir Vagaytsev
by
8.1k points
6 votes

Answer:


(1)/(7)

Solution,


{7}^( - 1) \\ = \frac{1}{ {7}^(1) } \\ = (1)/(7)

Laws of indices:

  • Law of zero index:


{x}^(0) = 1

  • Product law of indices:


{x}^(m) * {x}^(n) = {x}^(m + n)

( powers are added in multiplication of same base)

  • Power law of indices:


{( {x}^(m) )}^(n) = {x}^(m * n)

  • law of negative index:


{x}^( - m) = \frac{1}{ {x}^(m) }

  • Root law of indices:


{x}^{ (p)/(q) } = \sqrt[q]{ {x}^(p) }


  • ( (x)/(y) ) ^(n) = \frac{ {x}^(n) }{ {y}^(n) }

  • {(xy)}^(m) = {x}^(m) {y}^(m)

  • \sqrt[n]{x} = x (1)/(n)

Hope this helps ....

Good luck on your assignment...

Evaluate. Write your answer as a fraction or whole number without exponents. 7^–1 =-example-1
User RAGINROSE
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories