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2/3 - 5bx = bx + 1/3 In the equation shown above, b is a constant. For what value of b = NO SOLUTIONS? A. 5 B. 0 C. -5 D. 2/5

User Saralynn
by
8.5k points

2 Answers

1 vote

Answer:

−5

Explanation:

First, we observe that this is a linear equation.

A linear equation in one variable will have no solutions if the equation reduces to an equation of the form:

\blue a x+\red b=\blue c x + \red dax+b=cx+dstart color #6495ed, a, end color #6495ed, x, plus, start color #df0030, b, end color #df0030, equals, start color #6495ed, c, end color #6495ed, x, plus, start color #df0030, d, end color #df0030

where \blue a=\blue ca=cstart color #6495ed, a, end color #6495ed, equals, start color #6495ed, c, end color #6495ed and \red b\\eq \red db

=dstart color #df0030, b, end color #df0030, does not equal, start color #df0030, d, end color #df0030.

In this case, the equation will reduce to the statement \red b=\red db=dstart color #df0030, b, end color #df0030, equals, start color #df0030, d, end color #df0030, which is not true for any value of xxx.

Hint #2

Since \red {\dfrac23}\\eq \red {\dfrac13}

3

2

=

3

1

start color #df0030, start fraction, 2, divided by, 3, end fraction, end color #df0030, does not equal, start color #df0030, start fraction, 1, divided by, 3, end fraction, end color #df0030 , the equation will have no solutions if \blue b=\blue {-5}b=−5start color #6495ed, b, end color #6495ed, equals, start color #6495ed, minus, 5, end color #6495ed.

Let's check that this is the case. If we add \blue {5}{x}5xstart color #6495ed, 5, end color #6495ed, x to both sides, we get

\begin{aligned} \red{\dfrac23}\blue{-5}x&= \blue{-5} x+\red{\dfrac13}\\\\ \red{\dfrac23}\blue{-5}x+\blue5x&= \blue{-5}x+\blue{-5}x+\red{\dfrac13} \\\\ \red{\dfrac23}&=\red{\dfrac13} \end{aligned}

3

2

−5x

3

2

−5x+5x

3

2

=−5x+

3

1

=−5x+−5x+

3

1

=

3

1

which is not true for any value of xxx, so there are no solutions.

For all other values of b,b,b, comma there will be one solution.

Hint #3

If b=-5b=−5b, equals, minus, 5, the equation will have no solutions.

User Kennyg
by
8.5k points
3 votes

Answer:

B

Explanation:

Here, we want to know at what values of b does the equation becomes not solvable

Now looking at the left hand side, we have;

2/(3-5bx) and also the right hand side bx + 1/3

For this expression if we insert b = 0, then automatically x cancels out on both sides of the equation and we shall be left with nothing to solve

User Djn
by
8.1k points

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