Answer:
To break even the local arena must sell approximately 70,589 tickets. They would have a loss of $47625.
Explanation:
The cost per night of the Icey blades contract can be expressed as a function of the gate receipts, with the flat cost added by 40% of all the gate receipts sold. This expression is shown below:
![cost(x) = 60000 +0.4*x](https://img.qammunity.org/2021/formulas/mathematics/college/x6xogze5ahoyct078itrvtwu1gyec5tuud.png)
Since each ticket costs $1.25, then the revenue of the arena can be shown as:
![revenue(x) = 1.25*x](https://img.qammunity.org/2021/formulas/mathematics/college/vak4juo66ovev3x4ppqxcghok2xdnvepib.png)
In order to break even the revenue must be equal to the cost, so:
![revenue(x) = cost(x)\\1.25*x = 60000 + 0.4*x\\1.25*x - 0.4*x = 60000\\0.85*x = 60000\\x = (60000)/(0.85) = 70,588.24](https://img.qammunity.org/2021/formulas/mathematics/college/6u7s4j2hc6p00531hxv84oyizl1z0djxo3.png)
To break even the local arena must sell approximately 70,589 tickets.
If the average attendance was 7500 per night, the profit would be:
![profit = revenue(7500) - cost(7500)\\profit = 1.25*7500 - 60000 + 0.4*7500\\profit = 9375 - 60000 + 3000\\profit = -47625](https://img.qammunity.org/2021/formulas/mathematics/college/y9eq3nbdu85sh8k3w6o8h9s0m825tn6unl.png)
They would have a loss of $47625