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H(x)=1/8x^3-x^2 What is the average rate of change of h over the interval -2≤x≤2?

1 Answer

3 votes

Answer:


(1)/(2)

Explanation:

The average rate of change of h(x) in the closed interval [ a, b ] is


(h(b)-h(a))/(b-a)

Here [ a , b ] = (- 2, 2 ] , thus

h(b) = h(2) =
(1)/(8) (2)³ - 2² = 1 - 4 = - 3

h(a) = h(- 2) =
(1)/(8) (- 2)³ - (- 2)² = - 1 - 4 = - 5 , thus

average rate of change =
(-3-(-5))/(2-(-2)) =
(2)/(4) =
(1)/(2)

User Juan David Arce
by
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