Question

If P(x)= x3 –x2+1, Then P(0)+P(1) =

Answer 1

The answer to this question is 2

Answer 2

`p(0) + p(1) = 2`

Explanation:

=>
`p(x) = x^3-x^2+1`

Putting x = 0 in p(x)

=>
`p(0) = (0)^3-(0)^2+1`

=>
`p(0) = 0-0+1`

=>
`p(0) = 1`

Putting x = 1 in p(x)

=>
`p(1) = (1)^3-(1)^2+1`

=>
`p(1) = 1-1+1`

=>
`p(1) = 1`

So,

=>
`p(0)+p(1) = 1+ 1`

=>
`p(0) + p(1) = 2`