Question

A sample of carbon dioxide occupies 10.0 L under STP conditions. At what pressure wouldcthis same sample have a volume of 12.5 L and a temperature of 20.0oC?

Answer 1

Answer: 0.859 atm

Step-by-step explanation:

Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.

The combined gas equation is,

`(P_1V_1)/(T_1)=(P_2V_2)/(T_2)`

where,

`P_1` = initial pressure of gas (STP) = 1 atm

`P_2` = final pressure of gas = ?

`V_1` = initial volume of gas (STP) = 10.0 L

`V_2` = final volume of gas = 12.5 L

`T_1` = initial temperature of gas (STP) = 273K

`T_2` = final temperature of gas =
`20.0^0C=(273+20)K=293K`

Now put all the given values in the above equation, we get:

`(1* 10.0)/(273)=(P_2* 12.5)/(293)`

`P_2=0.859atm`

Thus at 0.859 atm , same sample have a volume of 12.5 L and a temperature of
`20.0^0C`