Question

Find the values of a, b, and c in the equation
below.
(x^5yz^4)^3/x^3yz=x^ay^bz^c

Answer 1

a=12

b=2

z=11

Explanation:

I got it right

Answer 2

a = 12, b = 2, z = 11

Explanation:

(x^5yz^4)^3/(x^3yz)

= (x^15y^3z^12)/(x^3yz)

= x^12y^2z^11

=> a = 12

=> b = 2

=> z = 11