Answer:
![(5)/(273)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/acg1pxhiiblas1mif568inebi41lhq3bjh.png)
They are dependent events.
Explanation:
Given:
Number of $1 gift certificates = 2
Number of $2 gift certificates = 2
Number of $3 gift certificates = 10
To find:
Probability that a $1 gift certificate is selected, then a $3 and then a $2 certificate is selected = ?
Solution:
First of all, let us learn about the formula of probability of any event E:
![P(E) = \frac{\text{Number of favorable cases}}{\text {Total number of cases}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/aeg3h4h3bbx73banosb6zhsdb88ck3qbng.png)
Finding probability of choosing $1 gift certificate in the first turn:
Number of favorable cases or number of $1 gift certificates = 2
Total number of cases or total number gift certificates = 2 + 2 + 10 = 14
So, required probability =
![(2)/(14) \Rightarrow (1)/(7)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/lsvwrluhjj2hvfjb7kqby97b7qq3kootrq.png)
Finding probability of choosing $3 gift certificate in the 2nd turn:
Number of favorable cases or number of $1 gift certificates = 10
Now, one gift certificate is already chosen,
So, Total number of cases or total number gift certificates = 14 - 1 = 13
So, required probability =
![(10)/(13)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/1hrtt9rjdnv9jmnditwtry5qnu29njgwyu.png)
Finding probability of choosing $2 gift certificate in the 3rd turn:
Number of favorable cases or number of $2 gift certificates = 2
Now, two gift certificates is already chosen,
So, Total number of cases or total number gift certificates = 14 - 2 = 12
So, required probability =
![(2)/(12) \Rightarrow (1)/(6)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/fd6r9g7s0okkf7rgou20f1fgwbvsvhx7gu.png)
Probability that a $1 gift certificate is selected, then a $3 and then a $2 certificate is selected:
![(1)/(7)* (10)/(13)* (1)/(6)\\\Rightarrow (5)/(273)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/keqfv7l40tgev4vekggdwftsf6csj2jk21.png)
They are dependent events because total number of cases and total number of favorable cases depend on the previous chosen gift certificate.
So, the answer is:
![(5)/(273)](https://img.qammunity.org/2021/formulas/mathematics/middle-school/acg1pxhiiblas1mif568inebi41lhq3bjh.png)
They are dependent events.