Question

How much energy in joules will be required to raise the temperature of 50.0 g of water from 20 degrees C to 60 degree C

Answer 1

Answer: 8368 Joules

Step-by-step explanation:

The quantity of heat required to raise the temperature of a substance by one degree Celsius is called the specific heat capacity.

`Q=m* c* \Delta T`

Q = Heat absorbed or released =?

c = specific heat capacity of water =
`4.184J/g^0C`

Initial temperature of water =
`T_i` =
`20^0C`

Final temperature of water =
`T_f` =
`60^0C`

Change in temperature ,
`\Delta T=T_f-T_i=(60-20)^0C=40^0C`

Putting in the values, we get:

`Q=50.0g* 4.184J/g^0C* 40^0C=8368J`

Thus energy in Joules required is 8368.