99.9k views
4 votes
Show all work to solve 3x^2-5x-2=0

Show all work to solve 3x^2-5x-2=0-example-1
User Deepflame
by
8.1k points

2 Answers

2 votes
1) Split the second term in 3x²-5x-2 into two terms.

•Multiply the coefficient of the first term by the constant term.
3 x -2 = -6

•Ask: Which two numbers add up to -5 and multiply to -6?
1 and -6

•Split -5x as the sum of and –6x.
3x2 + x – 6x – 2

2) Factor out common terms in the first two terms, then in the last two terms.

x(3x+1)-2(3x+1)


3) factor out the common term 3x+1.

(3x+1)(x-2)
User Otm
by
7.4k points
5 votes

Answer:

The roots are {2, -1/3}

Explanation:

The coefficients of this quadratic function are a = 3, b = -5 and c = -2.

Let's use the quadratic formula to find the roots of the given 3x^2-5x-2=0.

The discriminant is b^2 - 4(a)(c), or (-5)^2 - 4(3)(-2), or 25 + 24 = 49.

Thus, the roots are:

-(-5)±√49 5 ± 7

x = ---------------- = ------------ = 2 and -1/3

2(3) 6

User Vinniyo
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories