Question

Please help me fast

When iron rusts in air, iron(III) oxide is produced. How many moles of oxygen react with 80.9 mol of iron in the
rusting reaction?
4Fe(s) + 302(g) → 2Fe2O3(s)
Select one:
O a. 60.7
O b. 108
O c. 80.9
O d. 121

Answer 1

the answer is going to be A. 60.7 hope you have a good day

Answer 2

60.7 mole

Step-by-step explanation:

for every 4 moles of iron 3 moles of oxygen is used.

So, moles of oxygen =
`(3 * 80.9)/(4)` = 60.675