Question

Given that f(x)=x^-1, g(x)=2x+8 find (g-f)(10)

Answer 1

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Answer:

(g-f)(10) = 279/10.

Explanation:

Given:

`f(x) = x^(-1)`

and

`g(x) = 2x + 8`

Begin by solving for (g-f) by subtracting f(x) from g(x):

`(g-f)(x) = 2x + 8 - x^(-1)`

Substitute in 10 for x in the equation to solve this problem:

`(g-f)(10) = 2(10) + 8 - 10^(-1)`

Simplify:

`(g-f)(10) = 20 + 8 - (1)/(10)`

Create a common denominator to simplify further:

`(g-f)(10) = (200)/(10)+ (80)/(10) - (1)/(10)`

`(g-f)(10) = (279)/(10)`

Therefore:

(g-f)(10) = 279/10.