Question

Given the following equation: 2 KCIO, 2 KCI + 3 Oz, how many grams of Oz can

be produced by letting 8.00 moles of KCIO, react?​

Answer 1

Answer : The mass of
`O_2` produced is, 384 grams.

Explanation : Given,

Moles of
`KClO_3` = 8.00 mol

First we have to calculate the moles of
`O_2`

The balanced chemical equation is:

`2KClO_3\rightarrow 2KCl+3O_2`

From the reaction, we conclude that

As, 2 moles of
`KClO_3` react to give 3 moles of
`O_2`

So, 8.00 mole of
`KClO_3` react to give
`(3)/(2)* 8.00=12` mole of
`O_2`

Now we have to calculate the mass of
`O_2`

`\text{ Mass of }O_2=\text{ Moles of }O_2* \text{ Molar mass of }O_2`

Molar mass of
`O_2` = 32 g/mole

`\text{ Mass of }O_2=(12moles)* (32g/mole)=384g`

Therefore, the mass of
`O_2` produced is, 384 grams.