Answer:
Explanation:
Remark
The exposed perimeter of the triangle is just the two smaller legs of the right triangle (6 + 8) + 10 units at the bottom of the rectangle + two 1/2 circles.
The area of the figure is the area of the triangle at the top + the area of the two 1/2 circles + the rectangle in the middle.
Givens
- Shortest Triangle Leg = 6
- Middle Triangle Leg = 8
- Diameter of the 2 half circles
- pi = 3.14
- width of the rectangle in the middle = 8
- Length of the rectangle = 10
- d = 8
- r = d/2 = 8/2 = 4
Formula
A
Perimeter = 2 legs of the triangle + 2 half circles + bottom line
B
Area = (1/2) Leg1*leg2 + pi * r^2 + L * w
Solution
A Perimeter
Perimeter = 6 + 8 + 2*pi *r + 10
Perimeter = 24 + 2*3.14*4
Perimeter = 25.12
B Area
Area = 1/2 * 8 * 6 + 3.14*4^2 + 10* 8
Area = 24 + 50.24+ 80
Area = 150.24
Answer
P = 25.12
Area = 150.24