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Find all polar coordinates of point P = (2,14°)

User Thehale
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1 Answer

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Answer:


(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,194^(\circ) +360^(\circ)n).

Explanation:

If a point is
P=(r,\theta), the all polar coordinates are defined as

In radian :
(r,\theta +2n\pi)\text{ and }(-r,\theta +(2n+1)\pi)

In degree :
(r,\theta +360^(\circ)n)\text{ and }(-r,\theta +(2n+1)180^(\circ))

where, n is any integer.

The given point is


P=(2,14^(\circ))

So, all polar coordinates are


(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,14^(\circ) +(2n+1)180^(\circ))


(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,14^(\circ) +360^(\circ)n+180^(\circ))


(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,194^(\circ) +360^(\circ)n)

Therefore, the required polar coordinates are
(2,14^(\circ)+360^(\circ)n)\text{ and }(-2,194^(\circ) +360^(\circ)n), where n is any integer.

User JKraut
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