Question

Based on the emf value measured at frame 700, what is the average magnitude of the magnetic field inside the magnet assembly? Note that the loop has 10 turns; in other words, the total emf is the sum of the emf’s generated in each turn. In your calculations, use 26 mV for the magnitude of the total induced emf and 0.060 m/s for the speed of the loop.

Answer 1

To calculate the average magnitude of the magnetic field inside the magnet assembly, we can use the equation emf = NΔΦ/Δt and rearrange it to solve for the magnetic field. Given the values for the emf and the speed of the loop, we can substitute them into the equation and calculate the average magnitude of the magnetic field.

Step-by-step explanation:

To calculate the average magnitude of the magnetic field inside the magnet assembly based on the emf value measured at frame 700, we can use the formula:

emf = NΔΦ/Δt

Where emf is the induced emf, N is the number of turns (10 in this case), ΔΦ is the change in magnetic flux, and Δt is the change in time.

We are given that the total induced emf is 26 mV and the speed of the loop is 0.060 m/s. From here, we can rearrange the formula to solve for the average magnitude of the magnetic field (B):

B = (emf * Δt) / (N * ΔΦ)

Inserting the given values, we have:

B = (0.026 V * 0.100 s) / (10 * ΔΦ)

B = (0.0026 T * s) / (10 * ΔΦ)

Therefore, the average magnitude of the magnetic field inside the magnet assembly can be determined by calculating the value of ΔΦ.