Answer:
a
Explanation:
Recall that the "point-slope" form of a linear equation may be expressed as
y = mx + b,
where m is the gradient.
If m is negative, the gradient is negative.
If m is positive, the gradient is positive.
In our case, if we consider option A,
x + 3y = -2 (rearranging)
3y = -x -2
y = (-1/3) x - (2/3)
if we compare this to the general equation at the top, we can see that
gradient, = m = (-1/3) which is negative.
hence option a has a negative gradient.