Question

You are an ISP. For the Address Block 195.200.0.0/16 a. If you have 320 Customers that need 128 addresses/customer - will there be enough addresses to satisfy them? and explain why? b. Say the first block of 64 customers want 128 addresses/customer - what would the address space look like?

Answer 1

a. The network will not satisfy the customers because the required addresses is 128 but what can be offered is 126.

b. 195.200.0.0/22

Step-by-step explanation:

195.200.0.0/16

The number of bits to give 512 is 9

2^9=512

2^8=256 which is not up to our expected 320 customers that requires a network ip

Note we have to use a bit number that is equal or higher than our required number of networks.

The number of host per each subnet of the network (195.200.0.0/25) is (2^7)-2= 128-2=126

The network will not satisfy the customers because the required addresses is 128 but what can be offered is 126.

b. 64 customers requires 6 bits to be taken from the host bit to the network bit

i.e 2^6 = 64

195.200.0.0/22

The number of host per each subnet of the network (195.200.0.0/22) is (2^10)-2=1024 - 2 = 1022 hosts per subnet

This network meet the requirement " 64 customers want 128 addresses/customer "