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What is the equation of the line that is perpendicular to the given line and passes through the point (3, 0)? 3x + 5y = −9 3x + 5y = 9 5x − 3y = −15 5x − 3y = 15

2 Answers

3 votes

Answer:

D

Explanation:

Edgenuit* 2021

User Mohamida
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5 votes

Answer:

5x - 3y = 15

Explanation:

3x + 5y = −9 can be solved for y (and thus for the slope explicitly):

5y = -3x - 9, or y = (-3/5)x - 9/5. The slope of the given line is -3/5. The slope of a line perpendicular to the given line is the negative reciprocal of this -3/5, which is 5/3. Substituting 3 for x and 0 for y, our slope-intercept equation y = mx + b becomes 0 = (5/3)(3) + b, which leads to b = -5:

y = (5/3)x - 5. We must put this back into standard form, starting by multiplying all three terms by 3:

3y = 5x - 15, or -5x + 3y = -15. This is equivalent to 5x - 3y = 15 (which is the last answer choice).

User Enryu
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