Question

Aggregate blend composed of 65% coarse aggregate (SG 2.701), 35% fine aggregate (SG 2.625)

Compacted specimen weight in air = 1257.9 g, submerged weight = 740.0 g, SSD weight = 1258.7 g
Compacted specimen contains 5.0% asphalt by total weight of the mix with Gb = 1.030
Theoretical maximum specific gravity = 2.511
Bulk specific gravity of the aggregate __________
Bulk specific gravity of the compacted specimen__________
Percent stone __________
Effective specific gravity of the stone__________
Percent voids in total mix__________
Percent voids in mineral aggregate__________
Percent voids filled with asphalt__________

Answer 1

• 2.674
• 2.428
• 91.695%
• 2.592
• 3.305%
• 11.786%
• 78.1%

Step-by-step explanation:

coarse aggregate (ca) = 65%, SG = 2.701

Fine aggregate = 35%, SG = 2.625

A) Bulk specific gravity of aggregate

=
`(65*2.701 + 35*2.625)/(100) = 2.674`

B) Wm = 1257.9 g { weight in air }

Ww = 740 g { submerged weight }

therefore Bulk specific gravity of compacted specimen

=
`(Wm)/(Wm-Ww)` =
`(1257.9)/(1257.9 - 740 )` = 2.428

Theoretical specific gravity = 2.511

Percent stone

= 100 - asphalt content - Vv

= 100 - 5 - 3.305 = 91.695%

c) percent of void

=
`(9.511-2.428)/(2.511) * 100` Vv = 3.305%

d) let effective specific gravity in stone

=
`(91.695*unstone+ 5 *1.030 )/(96.695) = 2.511`

= Instone = 2.592 effective specific gravity of stone

e) Vv = 3.305%

f ) volume filled with asphalt (Vb) =
`((Wb)/(lnb) )/((Wm)/(Inm) ) * 100`

Vb =
`(5 * 2.428)/(1.030 * 100) * 100`

Vb = 11.786 %

Volume of mineral aggregate = Vb + Vv

VMA = 11.786 + 3.305 = 15.091

g) percent void filled with alphalt

= Vb / VMA * 100

VMA = 11.786 + 3.305 = 15.091

percent void filled with alphalt

= Vb / VMA * 100 = (11.786 / 15.091) * 100 = 78.1%